2y^2(3x+7y+2)=

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Solution for 2y^2(3x+7y+2)= equation: 


Simplifying
2y2(3x + 7y + 2) = 0

Reorder the terms:
2y2(2 + 3x + 7y) = 0
(2 * 2y2 + 3x * 2y2 + 7y * 2y2) = 0

Reorder the terms:
(6xy2 + 4y2 + 14y3) = 0
(6xy2 + 4y2 + 14y3) = 0

Solving
6xy2 + 4y2 + 14y3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
6xy2 + 4y2 + -4y2 + 14y3 = 0 + -4y2

Combine like terms: 4y2 + -4y2 = 0
6xy2 + 0 + 14y3 = 0 + -4y2
6xy2 + 14y3 = 0 + -4y2
Remove the zero:
6xy2 + 14y3 = -4y2

Add '-14y3' to each side of the equation.
6xy2 + 14y3 + -14y3 = -4y2 + -14y3

Combine like terms: 14y3 + -14y3 = 0
6xy2 + 0 = -4y2 + -14y3
6xy2 = -4y2 + -14y3

Divide each side by '6y2'.
x = -0.6666666667 + -2.333333333y

Simplifying
x = -0.6666666667 + -2.333333333y

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